Find EMF source E and Ammeter Reading in circuit
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An ideal voltmeter has infinite resistance, hence no current flows through it. An ideal ammeter has zero resistance. The current i through the resistor R.
i=
R+r
E
=
4+2
12
=2A
The ammeter will read i=2A
As there is no potential difference between points a and p or between points b and q, i.e., V
ab
=V
pq
,we find V
a
by considering a and b either as the terminals of the resistor or as the terminals of the source
V
pq
=IR=2×4=8V
Considering them as the terminals of the source, we have
V
ab
=E−ir=12−2×2=8V
Either way, we conclude that the voltmeter reads V
ab
=8V
by this method all these type of questions solved..
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