Question

find empirical formula of compound with following. percentage composition pb- 62.5% , N - 8.5% and O- 29%​

Answer 1

Answer:

atomic mass of Pb = 207 g/mol

atomic mass of N = 14 g/mol

atomic mass of O = 16 g/mol

percentage composition:

Pb = 62.5%, N = 8.5% and O = 29%

Now finding percentage mass ratio,

Pb 62.5/207= 0.3063

N→ 8.5/14 = 0.6071

O 29/16 = 1.8125

finding simple ratio of given elements,

Pb: N:O::0.3063: 0.6071: 1.8125

→ Pb: N:O::0.3:0.6: 1.8

→ Pb : N:O:: 1:2:6

hence, empirical formula of compound is

Pbn2o6