Question

find energy equivalent to the mass of zn where mass of zn =65.382 u​

Answer 1

Answer:

64,30Zn has 30 electrons, 30  protons and 34 neutrons. The expected mass of Zn is

30(0.000543)+30(1.00758)+34(1.00893)=64.54731 amu.

The actual mass is 63.92915 amu

The mass defect Δm=64.54731−63.92915=0.61816  amu ≃0.6 g/mol

The binding energy E=Δm×931.5 MeV =0.61816×931.5=575.816 MeV.

This binding energy is for 64 nucleons. For 1 nucleon, the binding energy will be 575.816/64=8.99

Explanation:

Brainy Lady

Answer 2

its simple multiply of mass in amu with c square value 931.5 MeV/u .

As i already taught in class :P