Question

Find energy of the photons which correspond to light of frequency 3x10¹⁵ Hz

Answer 1

Hey mate !!!

ν = 3× 10^15 Hz.

E = hν = (6.626×10-34 Js)×(3×1015 s-1)

= 1.988×10-18 J.

Hope this helps!!!

Answer 2

Vitality of photon = h × recurrence 6.626 × 10^ - 34 × 3 × 10 ^ 15 = 19.878 × 10 ^ - 19.

Through trials of frequencies and temperature, Planck could produce a consistent, Planck's steady h = 6.62607 x 10-34 J s

Using this consistent he could repeat his hypothesis:

vitality was specifically corresponding to recurrence.

He composed his condition as E=hν.