Physics, asked by gopalarao4444, 9 months ago

find equalent resistance

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Answered by taktushar8

1

Answer:

here is ur answer plzz mark it as brainliest

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Answered by brainlyaryan12

3

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$\huge{\orange{\fbox{\fbox{\blue{\bigstar{\mathfrak{\red{Answer}}}}}}}}$

$<marquee scrollamount = 700>✌️✌️✌️</marquee>$ $<marquee scrollamount = 500>⭐⭐⭐</marquee>$

In Circuit 1-

Total resistance = $R_p_1 + R_p_2$

➡️ $\frac{1}{R_{p1}} = \frac{1}{2} + \frac{1}{3}$

=> $\frac{1}{R_{p1}} = \frac{3+2}{6}$

=> $\frac{1}{R_{p1}} = \frac{5}{6}$

=> $R_{p1} = \frac{6}{5} \Omega$

➡️ $\frac{1}{R_{p2}} = \frac{1}{4} + \frac{1}{6}$

=> $\frac{1}{R_{p2}} = \frac{3+2}{12}$

=> $\frac{1}{R_{p2}} = \frac{5}{12}$

=> $R_{p2} = \frac{12}{5} \Omega$

Total resistance = $\frac{6}{5} + \frac{12}{5}$

=> $\frac{6+12}{5}$

=> $\large\orange{\fbox{\pink{Total\:resistance=\frac{18}{5} \Omega}}}$

In Circuit 2-

Total resistance = $R_{s1}+R_{s2}+R_{s3}$

➡️ $6 +7 + 3$

=> $\large\orange{\fbox{\pink{Total\:resistance= 16 \Omega}}}$

$\huge{\purple{\bigstar{\blue{\text{Hope it helps...}}}}}$

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