Question

find equation of a line with slope -3 and intersecting the X axis at a distance of 4 units to the left of origin​

Answer 1

Given ,

Slope of the line is -3 and intersecting the x axis at a distance of 4 units to the left of origin

It implies that ,

The line passes through (-4,0)

We know that ,

The point slope form is given by

$\mathtt{ \huge{ \fbox{m = \frac{ y_{2} - y_{1} }{x_{2} - x_{1}} }}}$

Substitute the known values , we get

$\sf \mapsto -3 = \frac{( y_{2}- 0)}{(x_{2} - (-4))} </p><p> \\ \\ \sf \mapsto - 3 = \frac{ (y_{2})}{(x_{2} + 4)} \\ \\ \sf \mapsto</p><p>-3x_{2}- 12 = y_{2} \\ \\ \sf \mapsto </p><p>3x_{2} + y_{2} + 12 = 0$

Hence , the equation of the line is 3x + y + 12 = 0