Question

Find equation of circle passing through point (2, 4) and having its centre at the point of

intersection of lines x – y = 4 and 2x + 3y =-7​

Answer 1

Answer:

YOUR ANSWER

The line x−y=4 and 2x+3y+7=0 intersect at the point (1,−3)

So, the centre of circle lies at (1,−3)

Point (2,4) lies on the circle.

So, radius = distance of (2,4) from (1,−3)

=(2−1)2+(4−(−3)2

=12+72

=50

=52 units

HOPE IT HELPS

Answer 2

Step-by-step explanation:

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