Question

Find equation of circle whose centre is (3,-4) and the line
3x-4y = 5 cuts circle at A and B , I (AB) = 6.​

Answer 1

Answer:

⊥r distance of line 2x−5y+18=0 from point

(3,-1)

h=∣∣∣∣22+522×3−5(−1)+18∣∣∣∣=2929=29

distance

⊥r  of (h,k)from

ax+by+c=0 is

∣∣∣∣a2+b2ah+bk+c∣∣∣∣

Thus r2=h2+32 [Pythagoras theorem in △OAC]

r2=29+9

r2=38

Thus eqn of circle is (x−3)2+(y+1)2=38.

Answer 2

Answer:

8ey y 8w5ce8w5ce7ce55ec7e7ceudcy says yes s y