Question

find equation of circle with centre at (-2,3) touching the X axis​

Answer 1

Answer:

x²+ y²+4x-6y+4=0

Step-by-step explanation:

given , the centre of the circle is at (-2,3)

comparing with general form (h,k) => h=-2 and k=3

also , given that the circle touches the x axis

=> the radius and the y ordinate of the centre should be same

so, r = 3

therefore the equation of the circle is,

(x-h)²+(y-a)² =a²        (considering the radius as a )

=> (x-(-2))²+(y-3)² = 3²

=> (x+2)²+(y-3)² = 9

=> x²+2(2)(x)+2² + y²-2(y)(3)+3² = 9

=> x²+4x+4 + y²-6y+9 = 9

=> x²+4x + y²-6y = 9-13

=> x²+ y²+4x-6y = -4

=> x²+ y²+4x-6y+4=0