Question

find equation of circle with centre at origin and radius 4

Answer 1

The equation of circle is,
(X-0)2+(Y-0)2=(4)2
Therefore,
X2+Y2=16

Answer 2

Equation of circle is $\bf \red{ {x}^{2} + {y}^{2} = 16}$.

Given:

• Centre of circle at origin and radius is 4 units.

To find:

• Find the equation of the circle.

Solution:

Equation of circle:

If a circle have centre at C(h,k) and it's radius is r units, then equation of circle is

$\bf ( {x - h)}^{2} + ( {y - k)}^{2} = {r}^{2}$

Step 1:

Write the given values.

As,

Centre of circle is at origin, i.e. C(0,0)

So,

$h= 0 \: and \: k= 0$

radius is $r=4$.

Step 2:

Write equation of circle.

Put the values.

$( {x - 0)}^{2} + ( {y - 0)}^{2} = {4}^{2}$

or

${x}^{2} + {y}^{2} = 16$

Thus,

Equation of circle is $\bf {x}^{2} + {y}^{2} = 16$.

Learn more:

1)Find the equation of the circle touching the lines x=0 y=0 and x=2c

https://brainly.in/question/7408360

2) find the angle between tangents drawn from (3,2) to circle x2+y2-6x+4y-2=0 explain with the process

https://brainly.in/question/28536112

#SPJ3