Find equation of diagonal of rectangle whose sudes are x=-1 x=4 y =-1 y=2
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From these lines we can find out that the four vertices of the rectangle have the coordinates (-1, -1), (-1, 2), (4, -1), (4, 2).
Consider the points (-1, -1) and (4, 2). They're diagonally opposite to each other.
Slope of the diagonal joining these points,
(2 + 1) / (4 + 1) = 3 / 5
Now we have the equation with (4, 2).
y - 2 = 3(x - 4) / 5
y - 2 = (3x - 12) / 5
5y - 10 = 3x - 12
3x - 5y - 2 = 0
So we got equation for a diagonal. Let's find the equation of the other.
This diagonal join the points (-1, 2) and (4, -1). So we have the slope,
(- 1 - 2) / (4 + 1) = - 3 / 5
Now the equation with (-1, 2),
y - 2 = - 3(x + 1) / 5
5y - 10 = - 3x - 3
3x + 5y - 7 = 0
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