Find equation of fangent and Normal to
the
curve. Y=x +48 +1 at pt (-1,2)
Answers
Answered by
1
Step-by-step explanation:
We have;
y
=
x
4
+
2
x
2
−
x
First we differentiate wrt
x
;
y
=
x
4
+
2
x
2
−
x
∴
d
y
d
x
=
4
x
3
+
4
x
−
1
We now find the vale of the derivative at
(
1
,
2
)
(and it always worth a quick check to see that
y
=
2
when
x
=
1
) we have
d
y
d
x
=
4
+
4
−
1
=
7
So at the tangent passes through the coordinate
(
1
,
2
)
and has gradient
m
=
7
We now use
y
−
y
1
=
m
(
x
−
x
1
)
to get the equation of the tangent:
∴
y
−
2
=
7
(
x
−
1
)
∴
y
−
2
=
7
x
−
7
∴
y
=
7
x
−
5
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