Question

find equation of image of circle whose equation is x2+y2+8x-16y+64=0 in the line mirror x=0

Answer 1

The equation given is

        x^2+y^2+8x-16y+64=0

Add and subtract 16 to the given equation.

 x^2 + 8x + 16 + y^2 - 16y + 64 -16 = 0

x^2 + 8x + 16 + y^2 - 16y + 64  = 16

(x - 4)^2 + (y - 8)^2 = 4^2 is the equation.

(x - (-4))^2 + (y - 8)^2 = 4^2 . centre is (- 4, 8)

         

Answer 2

Step-by-step explanation:

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