Question

Find equation of line having slope = - 3 and passing through point ( 1 , -3 ).​

Answer 1

y-(-3) = -3(x-1)

y+3= -3x+3

y = -3x

Answer 2

Given:

A line has slope = - 3 and passing through point ( 1 , -3 ).

To find:

Equation of line?

Calculation:

General equation of a straight line passing through points $(x_{1},y_{1})$ is:

$(y - y_{1}) = m(x - x_{1})$

$\implies \{y - ( - 3) \} = (- 3)(x - 1)$

$\implies y + 3 = - 3x + 3$

$\implies y + 3x = 0$

So, equation of straight line is :

$\boxed{ \bf y + 3x = 0}$