Question

Find equation of line passes through the
point (2,3) and (5-7)​

Answer 1

Answer:

10x+3y-59=0

Step-by-step explanation:

Let the given points are A(2,3) and B(5,-7)

first, assume (2,3) be (x1 ,y1) and(5,-7) be( x2,y2)

we need to find the slope m for the points A and B

m = $\frac{y_{2} -y_{1}}{x_{2}-x_{1} }$

so m= -10/3

Therefore equation of the line passing the given points is

$y-y_{1} = m (x-x_{1} )$

y-3= -10/3 (x-5)

3(y-3)= -10(x-5)

3y-9=-10x+50

10x+3y-59=0

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