Question

find equation of line passing through point(-2, 5) and having slope -3/4​

Answer 1

Answer:

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Step-by-step explanation:

$so \: for \: a \: certain \: line \\ given \: points \: are \: ( - 2,5) \\ let \: then \: ( - 2,5) = (x1,y1) \\ \\ its \: slope \: (m) = \frac{ - 3}{4}$

$so \: we \: know \: that \\ equation \: of \: slope \: point \: form \: is \: given \: by \\ (y - y1) = m(x - x1) \\ \\ (y - 5) = \frac{ - 3}{4} (x - ( - 2)) \\ \\ 4(y - 5) = - 3(x + 2) \\ 4y - 20 = - 3x - 6 \\ 3x + 4y - 14 = 0 \\ \\ hence \: equation \: of \: line \: passing \: through \: point \: (-2, 5) \: and \: having \: slope \: -3/4 \: \: is \\ 3x + 4y - 14 = 0$