Question

Find Equation of line passing through the point (3,4) and perpendicular to line 2x-4y+5=0​

Answer 1

Step-by-step explanation:

slope of line =(-2/4)=-1/2

slope perpendicular line to it

=(-1/m)=2

equation of line will be

y=mx+c

y=2x+c

It satisfies (3,4)

4=6+c or c=-2

so equation of line will be

y=2x-2

Answer 2

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2x - 4y + 5 = 0

=> 2x + 5 = 4y

=> (2x + 5) /4 = y

=> (2x/4) + (5/4) = y

=> (1x/2) + (5/4) = y

.•. slope ( m1 ) = 1/2

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Since the required line is perpendicular to the given line.

.•. slope of the required line = m2 = -1/m1 = -1/(1/2) = -2

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Point given = P(3,4) = P(x1 , y1)

Equation of required line :

y - y1 = m2(x - x1)

=> y - 4 = -2(x - 3)

=> y - 4 = -2x + 6

=> 2x + y - 4 - 6 = 0

=> 2x + y - 10 = 0

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