Question

find equation of line perpendicular to line √3x-y+5=0 at a distance of 5 unit from origin
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Answer 1

Given line

3

x−y+5=0

slope of line =

−1

−

3

=

3

slope of line perpendicular to given line = −

3

1

Let the required line by y=mx+c

⇒y=−

3

1

x+c =

3

x

+y−c=0

Given it is a distance of 3 units away from origin

(

3

1

)

2

+(1)

2

∣−c∣

=3

3

y

∣c∣

=3⇒∣c∣=

12

c=±

12

∴ The required line =

3

x

+y±

12

=0

solution