Find equation of line through the point of intersection of the line x+2y-3=0 and 4x-y+7=o and perpendicular to the line x-2y=7
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The equation of given lines are,
The equation of line passing through the intersection of given line (1) and (2) is as,
Given, this line (4) is parallel to given line,
So, Slope of line (5) = Slope of line (4)
−54 = −4λ + 12 − λ⇒54 = 4λ + 12 − λ⇒16λ + 4 = 10 − 5λ⇒21λ = 6⇒λ =27
Substitute value of in equation (3), we get,
Hence, equation of line through the intersection of line (1) and (2) and parallel to line (5) is 15x+12y-7=0.
keshav yaduvanshi
my whatsapp no 9675624741
The equation of line passing through the intersection of given line (1) and (2) is as,
Given, this line (4) is parallel to given line,
So, Slope of line (5) = Slope of line (4)
−54 = −4λ + 12 − λ⇒54 = 4λ + 12 − λ⇒16λ + 4 = 10 − 5λ⇒21λ = 6⇒λ =27
Substitute value of in equation (3), we get,
Hence, equation of line through the intersection of line (1) and (2) and parallel to line (5) is 15x+12y-7=0.
keshav yaduvanshi
my whatsapp no 9675624741
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