find equation of normal to the curve y =
where normal is parallel to the line x-2y+10=0
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Answered by
0
Answer:
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Step-by-step explanation:
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Answered by
0
Answer
=3x
2
+2
1
,y
1
)
1
,y
1
) is
(
dx
dy
)
(x
1
,y
1
)
=3x
1
2
+2
1
,y
1
) is
1
,y
1
)
−1
=
3x
2
+2
−1
y=−
14
1
x−
14
4
= −
14
1
∴
3x
1
2
+2
−1
=
14
−1
⇒3x
1
2
+2=14
⇒3x
1
2
=12
x
1
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