Math, asked by poojarani4208, 15 days ago

find equation of normal to the curve y =
 {x}^{3 }  + 5 {x}^{2}  - 10x + 11
where normal is parallel to the line x-2y+10=0​

Answers

Answered by tanujp392
0

Answer:

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Step-by-step explanation:

follow please

Answered by sunprince0000
0

Answer

=3x  

2

+2

1

,y  

1

)

1

,y  

1

) is  

(  

dx

dy

)  

(x  

1

,y  

1

)

=3x  

1

2

+2

 

1

,y  

1

) is  

 

1

,y  

1

)

−1

 

=  

3x  

2

+2

−1

 

 

y=−  

14

1

x−  

14

4

 = −  

14

1

 

∴  

3x  

1

2

+2

−1

=  

14

−1

 

⇒3x  

1

2

+2=14

⇒3x  

1

2

=12

x  

1

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