Question

find equation of perpendicular bisector of the line segment joining the points (0,3) and (-4,1)
Please Give the Right Answer
It is A question of Straight line - Class 11​

Answer 1

Answer:

The right bisector of a line segment bisects the line segment at 90  

∘

.  

The end-points of the line segment are given as A(3,4) and B(−1,2).

Accordingly, mid-point of AB ={  

2

3−1

​

,  

2

4+2

​

}=(1,3)

and slope of AB =  

−1−3

2−4

​

=  

−4

−2

​

=  

2

1

​

 

∴ slope of line perpendicular to AB =−  

{  

2

1

​

}

1

​

=−2

Thus equation of the line passing through (1,3) and having a slope of −2 is given by,  

(y−3)=−2(x−1)

⇒y−3=−2x+2⇒2x+y=5

Thus, the required equation of the line is  2x+y=5.

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

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