Question

find equation of side of equilateral triangle whose vertex (1,2) and bases Y =0
plzz solve fast with figure plzzz​

Answer 1

Step-by-step explanation:

the equation of the left line is:

y=x√3+2+√ 3

the equation of the right line is:

y=-x√3+2-√ 3

The base is the y axis and the height is 2. The equation of a straight line is:

slope=m=Δy/Δx=(y−yp)/(x−xp)

Where (xp,yp) are the coordinates of a point on the line. Take the top vertex as that point for the two sides and solve for y :

y=mx+2+m

The slope of the left side is: m=tan60=√3

So the equation of the left line is: y=x√3+2+√ 3

The slope of the right side is: m = tan120 = −√3

So the equation of the right line is: y=−√3+2−√3