Find equation of straight line (2, 1) and bisecting the portion of the straight line 3x-5y=15 lying between the axes
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Step-by-step explanation:
3x-5y=15
the given line cuts x axis at 5,0
and y axis at ( 0,-3)
the point of bisection is (5/2,-3/2).
and now the equation of such a line is y+5x-11=0.
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