Math, asked by ekhlaquehussain7934, 1 day ago

Find equation of straight line passing through the point (2,5)and with ratio of x intercept to Y intercept is 2:5

Answers

Answered by senboni123456
0

Answer:

Step-by-step explanation:

Let x-intercept and y-intercept of the line be 'a' and 'b'

It is given that a : b = 2 : 5

\sf{\implies\,\dfrac{a}{b}=\dfrac{2}{5}}

\sf{\implies\,a=\dfrac{2b}{5}\,\,\,\,\,\,\,\,\,\,...(1)}

We know, equation of a line in intercept form is given by

\tt{\dfrac{x}{a}+\dfrac{y}{b}=1}

where 'a' and 'b' are x and y-intercepts

So, the equation of the line

\tt{\dfrac{x}{\dfrac{2b}{5}}+\dfrac{y}{b}=1}

\tt{\implies\dfrac{5x}{2b}+\dfrac{y}{b}=1}

Now, the line passes through (2,5)

So,

\tt{\implies\dfrac{5\times2}{2b}+\dfrac{5}{b}=1}

\tt{\implies\dfrac{5}{b}+\dfrac{5}{b}=1}

\tt{\implies\dfrac{10}{b}=1}

\tt{\implies\,b=10}

So,

\tt{\implies\,a=\dfrac{2\times10}{5}}

\tt{\implies\,a=2\times2}

\tt{\implies\,a=4}

Hence, the required equation of the straight line is

\sf{\dfrac{x}{4}+\dfrac{y}{10}=1}

\sf{\implies5x+2y=20}

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