Question

Find equation of tangent and normal to circle 2x^2+2y^2+3x-4y+1 at point (-1,2)​

Answer 1

Correct option is B)

Center of the circle is (

4

3

,1)

Distance of point B from the center of the circle is 2−

4

3

=

4

5

The radius of the circle is given by

(

4

3

)

2

+(1)

2

=

(

4

5

)

Since distance between point B and the center of the circle equals the radius and a tangent touches the circle at only one point, A has to coincide with B.

∴AB=0