Question

find equation of the line parallel to the line 3x-4y-12=0 and which is at a distance of 2 units from it​

Answer 1

Answer:

3x-4y=22

Step-by-step explanation:

Let the required line equation be L

where, P=> 3x-4y-12=0

The slope of the required line = 3/4 ;y=3x/4-3

Which is in the form of y=mx+c where m= slope

Take a point on the line P(x1,y1)

Given that the perpendicular distance (or) the distance b/w the parallel lines is 2

2=3x1-4y1-12/√(3^2+4^2)

2=3x1-4y1-12/5

10=3x1-4y1-12

3x1-4y1=22

We can replace (x1,y1) with (x,y) to get the line equation

So, the final answer is

3x-4y=22