Question

find equation of the line parallel to the line 3x-4y+2=0 and passing through the point (-2,3)

Answer 1

Answer:

The equation of the required line is 3x-4y+18=0

Step-by-step explanation:

$\bf{Concept:}$

$\text{Equation of any line parallel to ax+by+c=0 and passing through the point (x_1,y_1) is }\\\\\boxed{\bf\;ax+by=ax_1+by_1}$

$\text{Given line is 3x-4y+2=0}$

$\text{The equation of the line parallel to 3x-4y+2=0 can be put in the form}\\\\3x-4y=3x_1-4y_1$

$\text{Here,}(x_1,y_1)=(-2,3)$

$\implies\;3x-4y=3(-2)-4(3)$

$\implies\;3x-4y=-6-12$

$\implies\;3x-4y=-18$

$\implies\boxed{\bf{3x-4y+18=0}}$