Math, asked by pranitiparmar3916, 1 year ago

Find equation of the plane passing through the point (2,3,5) and perpendicular to the line whose d.r.s. are 3, –2, 6.

Answers

Answered by manjusha12
0

the equation of a plane passes through a point (x1,y1,z1) and drs(a,b,c) is

a(x-x1)+b(y-y1)+c(z-z1)=0

3(x-2)-2(y-3)+6(z-5)=0


manjusha12: answer is 3x-2y+6z-30=0
Similar questions