Find equation of the plane passing through the point (2,3,5) and perpendicular to the line whose d.r.s. are 3, –2, 6.
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the equation of a plane passes through a point (x1,y1,z1) and drs(a,b,c) is
a(x-x1)+b(y-y1)+c(z-z1)=0
3(x-2)-2(y-3)+6(z-5)=0
manjusha12:
answer is 3x-2y+6z-30=0
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