Question

find equation to the circle Passing through the point:(0, 1), 1,0), (2,1)​

Answer 1

Answer:

Let centre of circle be (α,β)

∴(α−1)

2

+(β−0)

2

=(α−0)

2

+(β−1)

2

∴α

2

−2α+1+β

2

=α

2

+β

2

−2β+1

⇒α=β

And

(α−1)

2

+(β−0)

2

=(α−1)

2

+(β+2)

2

⇒β

2

=β

2

+4β+4

⇒β=−1=α

∴ Radius of circle =

(α−1)

2

+(β−0)

2

=

(−1−1)

2

+(−1)

2

=

5

∴ equation of circle :- (x+1)

2

+(y+1)

2

=5