Question

Find equation using suitable identity (2x+4y) 2

Answer 1

Solution :

$\large \sf : \implies(2x + 4y {)}^{2} \\ \\\large \sf : \implies {(2x)}^{2} + {(4y)}^{2} + 2 \times 2x \times 4y \\ \\ \large \sf : \implies {4x}^{2} + {16y}^{2} + 16xy$

IdentitY Used :

$\large \sf : \implies(a + b {)}^{2} = a^2 + b^2 + 2ab$

Answer 2

$\large\bf\underline{Given:-}$

= ( 2x+4y )²

$\large\bf\underline{To\:find:-}$

★ Equation using suitable identity ( 2x+4y )²

$\large\bf\underline{Identity:-}$

(a+b)² = a² + b² + 2ab

$\large\bf\underline{Solution:-}$

a = 2x

b = 4y

★ Put the values in the identity .

= (2x)² + (4y)² + 2× (2x) × (4y)

= 4x² + 16y² + 16xy

_______________________

$\large\bf\underline{Answer:-}$

★ 4x² + 16y² + 16xy