Find equations of lines which contains
the point A(1,3) and the sum of whose
intercepts on the co-ordinate axes is zero.
Answers
Answered by
63
Answer:
x - y + 2 = 0
Step-by-step explanation:
Let the equation of the line is
x/a + y/b = 1 ..... (1)
where a and b are x and y axes intercepts.
By the given condition,
a + b = 0 ..... (2)
Also given that the point A (1, 3) lies on line (1), then
1/a + 3/b = 1
or, 1/(- b) + 3/b = 1 [ by (2) ]
or, 2/b = 1
or, b = 2
Then from (2), a = - 2
So the equation of the line is
x/(- 2) + y/2 = 1
or, x - y + 2 = 0
Therefore the required line is
x - y + 2 = 0
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