find equations of parabola vertex 4,1 focus 4,-3
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Points (4,−3) and (4,−1) lie on the line x=4.
So, the axis of parabola is the line x=4.
So, the equation of parabola is (x−4)2=−4a(y+1)
Distance between focus and vertex =−1−(−3)=2.
∴a=2.
So, the equation of parabola is (x−4)2=−4(2)(y+1)
⟹x2−8x+16+8y+8=0.
⟹x2−8x+8y+24=0.
Step-by-step explanation:
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