Find equations of tangent and normal to the ellipse x2 a2 y2 b2 = 1
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Answer:
Correct option is
C
x−ey−ae
3
=0
The end of the latus rectum in the first quadrant is (ae,
a
b
2
)
Equation of normal at (ae,
a
b
2
) is
ae
a
2
x
−
b
2
/a
b
2
y
=a
2
−b
2
[
x
1
a
2
x
−
y
1
b
2
y
=a
2
−b
2
]
⇒
e
a
x−ay=a
2
e
2
[∵e
2
=
a
2
a
2
−b
2
]
⇒x−ey−ae
3
=0
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