Question

Find equations of tangent and normal to the ellipse x2 a2 y2 b2 = 1

Answer 1

Answer:

x-ey-ae^3 =0

Step-by-step explanation:

The end of the latus rectum in the first quadrant is (ae, b^2/a)

Equation of normal at (ae, b^2/a) is

a^2x/ae - b^2y/b2/a = a^2 -

b^2 [a^2x/x1 - b^2/y1 = a^2 - b^2]

⇒ a/e x - ay = a^2e^2

= [e^2 = a^2 -b^2/a^2]

⇒ x-ey-ae^3 =0