Find equivalent capacitance of the grouping across AB as shown in figure
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u have to assume the repeating part of the capacitors as x
for the part excluding 1C the net capacitance is :
1/2+1/1+x=1/x
x+3/2+2x=1/x
x^2+x-2=0
x=1
now
1C and x are in parallel so
1+1=2C
option 4
(nice to see that someone goes to Aakash....all the best)
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