Question

find equivalent resistance​

Answer 1

ᴀɴsᴡᴇʀ-:

In the first circuit, let upper be the R1... which is in parallel with other two resistance, R2 and R3.

Between A and D

Rs = R2+R3

=2+2

=4

$\frac{1}{Rp} = \frac{1}{r1} + \frac{1}{rs} \:$

$= \frac{1}{2} + \frac{1}{4} \:$

$= \frac{2 + 1}{4} \:$

$= > \frac{1}{rp} = \frac{3}{4} \:$

$rp = \frac{4}{3}$

In the second circuit, from D to B,let it R4 and the other below as R5

$\frac{1}{rp} = \frac{1}{r4} + \frac{1}{r5}$

$= \frac{1}{2} + \frac{1}{2}$

$= \frac{1 + 1}{2}$

$rp = \frac{2}{2}$

$rp = 1$

Now, there are only two resistance left, that is 4/3 and 1.

They are in parallel, so...

$\frac{1}{rp} = \frac{4}{3} + \frac{1}{1}$

$\frac{1}{rp} = \frac{7}{3}$

$rp = \frac{3}{7}$

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