Physics, asked by sarojbhati, 8 months ago

Find equivalent resistance

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Answered by navnathblp
4

Answer:

arre bhiwa itna tough kis kitab me sawal hai kitab ka nam send kar sakte hoo.....

kaphi time taking tha....

please like my answer at least....

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Answered by jigyasa0310
3

Answer:

equivalent \: resistance = (4ohm \:  + 1 ÷ ( \frac{1}{1} ohm +  \frac{1}{2} ohm +  \frac{1}{3} ohm) + 1÷ (  \frac{1}{5} ohm +  \frac{1}{6} ohm) ) +  \frac{1}{7} ohm \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  = 1÷(4ohm +  \frac{6}{11} ohm +  \frac{30}{11} ohm) +  \frac{1}{7} ohm \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 1÷( \frac{11}{80} ohm +  \frac{1}{7} ohm )\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  1÷\frac{167}{560} ohm= 3.57 ohm

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