find equivalent resistance.
Answers
Solution:
We have to determine the equivalent resistance of the circuit.
We can observe that the resistances 10 Ω, 10 Ω and 5 Ω are in parallel combination.
Let the equivalent resistance here be R.
Therefore:
→ 1/R = 1/10 + 1/10 + 1/5
→ 1/R = 2/10 + 1/5
→ 1/R = 1/5 + 1/5
→ 1/R = 2/5
→ R = 5/2 Ω
→ R = 2.5 Ω
Now, the resistances 5 Ω, 2.5 Ω and 20 Ω are in series.
Therefore, the equivalent resistance will be:
→ Equivalent Resistance = (5 + 2.5 + 20) Ω
→ Equivalent Resistance = 27.5 Ω
★ Which is our required answer.
Answer:
- The equivalent resistance in the circuit system is 27.5 Ω
Additional Information:
Let R₁, R₂ and R₃ be 3 resistors connected in series. Let Rₛ be the equivalent resistance of the circuit.
Then:
→ Rₛ = R₁ + R₂ + R₃
If they were connected in parallel combination, then:
→ 1/Rₛ = 1/R₁ + 1/R₂ + 1/R₃
The SI unit of resistance is ohm. It is denoted by the Greek letter Ω (Omega)