Find equivalent resistance :
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Heya!!
Start by LHS;
AF & FE are in series in parallel with AE :
Hence 1/R = 1/6 + 1/6
=) 1/R = 1/3
=) R(AE) = 3 ohms
Again AE & DE are in series in parallel with AD:
=) 1/R = 1/6 + 1/6
=) 1/R =1/3
=) R(AD) = 3 ohms
Again AD & DC are in series in parallel with AC:
=) 1/R = 1/6 + 1/6
=) 1/R = 1/3
=) R(AC) = 3 ohms
Again AC & BC are in series in parallel with AB:
=) 1/R = 1/6 + 1/3
=) 1/R = 1/2
Hence R (AB) = 2 ohms.
Hope it helps uh!!
Start by LHS;
AF & FE are in series in parallel with AE :
Hence 1/R = 1/6 + 1/6
=) 1/R = 1/3
=) R(AE) = 3 ohms
Again AE & DE are in series in parallel with AD:
=) 1/R = 1/6 + 1/6
=) 1/R =1/3
=) R(AD) = 3 ohms
Again AD & DC are in series in parallel with AC:
=) 1/R = 1/6 + 1/6
=) 1/R = 1/3
=) R(AC) = 3 ohms
Again AC & BC are in series in parallel with AB:
=) 1/R = 1/6 + 1/3
=) 1/R = 1/2
Hence R (AB) = 2 ohms.
Hope it helps uh!!
alisha894:
correct.. thnku
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