Find equivalent resistance across A and B
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nawalsaniya:
Rab= 2
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Answered by
1
first add series 3+3=6 and 6+6=12
then in parallel 1/12+1/6= 3/122
therefore equivalent resistance is equal 12/3=4
Answered by
1
Rs=3+3=6
Rs=6+6=12
Rab =1/6+1/12=12×6/12+6=72/18=4
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