find equivalent resistance across a-b
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let the 10 ohm resistance be r1
let 2 ohm and 6 ohm resistance be R2, they are In parallel
so 1/R2 = 1/2+1/6=2/3
R2 = 3/2
let r3 = 4ohm and 2 ohm
they are in parallel so
1/r3 = 1/4+1/2
r3= 4/3
now the R2 and r3 are in series and r1 is parallel to them
so R2 +r3= 3/2+4/3
R2+r3 = 17/6
now ,
1/ R total = 1/r1 + 1/R2 + r3
1/ R total = 1/10+ 6/17
1/ R total= 77/170
R total= 170/ 77
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. Hope it helps!!!
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