Question

Find equivalent resistance and current flowing through following electric circuit.​

Answer 1

Answer:

Here is yours answer

Explanation:

Solution

Since, resistors 1Ω and 3Ω are in series,
∴R
eq1
​
=1+3=4Ω
Now, resistors 4Ω and 6Ω are in parallel,
∴R
eq2
​
=4Ω∥6Ω=
4+6
4×6
​
=
10
24
​
=2.4Ω
Now, 3.6Ω,2.4Ω and 3Ω are again series,
∴R
eq
​
=3.6+2.4+3=9Ω
Now, the current flowing the electric current I
I=
R
eqAnswer
​

V
​

⇒I=
9
4.9
​
=0.5Amp
⇒I=0.5Amp