Question

FIND EQUIVALENT RESISTANCE OF THE FOLLOWING COMBINATION.​

Answer 1

Given

• Four resistors of 2Ω are connected parallely. They further are connected in series with a 20Ω resistor

To Find

• Equivalent resistance

Solution

☯ The equivalent resistance of a parallel combination is given by, 1/R = 1/R₁ + 1/R₂ ... + 1/Rₙ

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✭ According to the Question :

➞ 1/R = 1/R₁ + 1/R₂ ... + 1/Rₙ

➞ 1/R = 1/2 + 1/2 + 1/2 + 1/2

➞ 1/R = (1+1+1+1)/2

➞ 1/R = 4/2

➞ 1/R = 2/1

➞ R = 1/2

➞ R = 0.5 Ω

• So then Rₙₑₜ = 0.5 + 20 [Bcz they are connected in series]
• Rₙₑₜ = 20.5Ω

Answer 2

Explanation:

solution :

• = 3 is the answer