Question

find equivalent resistance of this circuit diagram? ​

Answer 1

Answer:

a circuit with three resistor in combination of parallel and series, a 4V battery and an ammeter, A.

To find (A) equivalent resistance, (B) current shown by the ammeter A

Solution:

Let, R

1

=5Ω,R

2

=3Ω,R

3

=2Ω,V=4V

And let the total current flowing in the circuit be I

From the circuit, it is clear that R

2

and R

3

are in series,

Therefore, R

s

=R

2

+R

3

=3+2=5Ω

And this series combination is in parallel with R

1

,,

Therefore, the equivalent resistance of the circuit is,

R

eq

=

R

1

+R

s

R

1

×R

s

⟹R

eq

=

5+5

5×5

⟹R

eq

=

10

25

=2.5Ω

Now Net current in the circuit is, I=

R

V

=

2.5

4

=1.6A

So the ammeter reading is 1.6A