Question

Find equivalent resistance Please answer it urgently

Answer 1

R1 = 4 Ohm

1/R2 = 1/1 + 1/2 + 1/3 = 6+3+2/6

R2 = 6/11 Ohm

R3 = 1/5 + 1/6

R3 = 30/11 Ohm

Rs = R1 + R2 + R3

Rs = 4+6/11 + 30/11

Rs = 80/11 Ohm

R4 = 7 Ohm

1/Rp = 1/7 + 80/11

1/Rp = 11+80/77

Rp = 77/91

Answer 2

Answer

14.27 Ω

Explanation

1 Ω , 2Ω , 3Ω are in parallel.

⇒ 1/R₁₂₃ = 1/R₁ + 1/R₂ + 1/R₃

⇒ 1/R₁₂₃ = 1/1 + 1/2 + 1/3

⇒ 1/R₁₂₃ = 3/2 + 1/3

⇒ 1/R₁₂₃ = 11/6

⇒ R₁₂₃ = 6/11

Now , 5 Ω , 6Ω are in parallel .

⇒ 1/R₅₆ = 1/R₅ + 1/R₆

⇒ R₅₆ = R₅.R₆ / R₅ + R₆

⇒ R₅₆ = 5.6/5+6

⇒ R₅₆ = 30/11

Now , 4Ω , R₁₂₃ , R₅₆  are in Series

⇒ R₁₂₃₄₅₆ = 4 + R₁₂₃ + R₅₆

⇒ R₁₂₃₄₅₆ = 4 + 6/11 + 30/11

⇒ R₁₂₃₄₅₆= 4 + 36/11

⇒ R₁₂₃₄₅₆ = (44 + 36) / 11

⇒ R₁₂₃₄₅₆ = 80/11

Now 7Ω , R₁₂₃₄₅₆ are in series

⇒ R_eq = 7 + 80/11

⇒ R_eq = 77 + 80 / 11

⇒ R_eq = 157 / 11

⇒ R_eq = 14.27 Ω