Question

find equivalent weight of (COOH)2.2H2O

Answer 1

Equivalent weight of (COOH)2.2H20.
=126/2=63.Normality of oxalic acid(N).
=evv×100°6363 1000 250°

Answer 2

Given:

Formula of the substance = $(COOH)_2.2H_2O$

To find:

Equivalent weight of $(COOH)_2.2H_2O$ = ?

Formula to be used:

Equivalent weight = $\frac{Molar mass}{n-factor}$

Calculation:

The molar mass of $(COOH)_2.2H_2O$ = 2(C)+4(O)+2(H)+4(H)+2(O)

Mass of $(COOH)_2.2H_2O$ = 2(12) +4(16)+2(1)+4(1)+2(16)

Mass of $(COOH)_2.2H_2O$ = 24+64+2+6+32 = 126g

The n-factor for $(COOH)_2.2H_2O$ is 2.

Thus the equivalent weight of $(COOH)_2.2H_2O$ is

$Equivalent weight = \frac{Molar mass}{n-factor}$ = $\frac{126}{2} = 63$

Conclusion:

The equivalent weight of $(COOH)_2.2H_2O$ is 63g.

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