Find eth area of traingle abc whose vertices are a(4,4)b(0,0) and c(6,2)
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vertices of triangle=(a)(4,4)=(x1,y1),(b)(0,0) = (x2,y2)&(c)(6,2)=(x3,y3)
area of triangle=1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=1/2(4(0-2)+0(2-4)+6(4-0))
=1/2(-8+0+24)=1/2×16=8.
area of triangle=1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=1/2(4(0-2)+0(2-4)+6(4-0))
=1/2(-8+0+24)=1/2×16=8.
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