Question

Find f (0) fro polynomial f(x) = x2 + x - 1​

Answer 1

✧$\huge \mathcal \red {\underline{\underline{A}}}$ $\huge \mathcal \green {\underline{\underline{N}}}$ $\huge \mathcal \pink {\underline{\underline{S}}}$ $\huge \mathcal \blue {\underline{\underline{W}}}$ $\huge \mathcal \orange {\underline{\underline {E}}}$ $\huge \mathcal \purple {\underline{\underline{R}}}$✧

❥ Given :

$\textsf {f(x) = x² + x - 1}$

❥ To Find :

$\textsf { f(0)}$

❥ Solution :

$\textsf { f(x) = x² + x - 1}$

$\textsf {Put 0 in the place of x}$

$\textsf {f(0) = 0² + 0 - 1}$

$\textsf {f(0) = 0 - 1)}$

$\textsf {f(0) = - 1}$

$\implies \textbf {Hence, f(0) is - 1.}$

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Answer 2

Answer:

-1

Step-by-step explanation:

f(x) = x² + x - 1

f(0)= 0² + 0 - 1

= -1