Question

Find f'(2) and f'(5), where f(x) = x2 + 7x + 4​

Answer 1

The value of  $f'(2)$ and $f'(5)$ in $f(x)=x^{2}+7x+4$ is $f'(2)=11,$$f'(5)=17.$

Step-by-step explanation:

Given:

$f(x)=x^{2}+7x+4$

To find:

$f'(2)$

$f'(5)$

Solution:

$f(x)=x^{2}+7x+4$

Differentiate the equation with respect to $x$,

⇒ $f'(x)=2x+7+0$

⇒$f'(x)=2x+7$

where $x=2$,

⇒$f'(2)=2(2)+7$

⇒$f'(2)=11$

where $x=5$,

⇒$f'(5)=2(5)+7$

⇒$f'(5)=17$

So the final answer is $f'(2)=11$ , $f'(5)=17$ .