find f(2),f(-2)and f(0) of the polynomial f (x) =(x+4)(x-5)
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Answer:
f(x)=(x+4)(x-5)................(1)
put x=2
f(2)=(2+4)(2-5)
=6*-3
=-18 (ans)
put x=-2 in eqn 1
f(-2)=(-2+4)(-2-5)
=2*(-7)
=-14. (ans)
put x=0 in eqn 1
f(0)= (0+4)(0-5)
=4*-5
= -20 (ans)
there fore f(2)=-18
f(-2)=-14
f(0)=-20 ......
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